WebOct 6, 2010 · T Get (int id) where T : EntityBase { Type context = Context.GetType (); MethodInfo getMethod = context.GetMethod ("Get", BindingFlags.Public); MethodInfo genericGet = getMethod.MakeGenericMethod (new [] {typeof (T)}); return (T)genericGet.Invoke (Context, new object [] { id } ); } Share Improve this answer Follow WebMar 27, 2024 · c# interface I where T : I { static virtual void M() {} static virtual T P { get; set; } static virtual event Action E; static virtual T operator + (T l, T r) { throw new NotImplementedException (); } } Explicitly non-virtual static members
What is the nicest way to dynamically implement an interface in C#?
WebFeb 13, 2024 · In C#, every executed instruction is performed in the context of a method. The Main method is the entry point for every C# application and it's called by the common language runtime (CLR) when the program is started. In an application that uses top-level statements, the Main method is generated by the compiler and contains all top-level … WebOct 24, 2008 · 1327. You need to use reflection to get the method to start with, then "construct" it by supplying type arguments with MakeGenericMethod: MethodInfo method = typeof (Sample).GetMethod (nameof (Sample.GenericMethod)); MethodInfo generic = method.MakeGenericMethod (myType); generic.Invoke (this, null); For a static method, … michael t gibbons
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WebFeb 16, 2024 · If you could guarantee that the static methods existed and would all have the same signature then you could create an array of those method, like methods = new Action[] { staticClass1.DemoMethod, … Web3 Answers. Sorted by: 1. The method FullPrint receives an instance of some type that implements ITest. An interface, for this example the one named ITest, is essentially a contract definition. It is a promise that any types that implement that interface will contain the defined methods and properties of that interface. WebMar 8, 2013 · You need to use the IMyInterface type to gain access to and subsequently invoke the method: int response = (int) (typeof (IMyInterface).InvokeMember ( "InterfaceMethod", BindingFlags.InvokeMethod BindingFlags.Instance BindingFlags.Public, null, instance, methodData)); Share Improve this answer Follow … michael t gibson